So I have a demand of 1.6 KWh/day, and insolation is 5.5 kwh/M^2day.
If the world was perfect, I'd just divide to get panel area.
It's not, so I assume there are other factors I must
include; the panel efficiency of course, and some electrical
losses. [It's a DC pump motor, so that eliminates one,
conversion losses..]
Where do I go for more data on this aspect?
--
A host is a host from coast to coast.................wb8foz@nrk.com
& no one will talk to a host that's...
calculating loses
If the world was perfect, I'd just divide to get panel area.
It's not, so I assume there are other factors I must
include; the panel efficiency of course, and some electrical
losses. [It's a DC pump motor, so that eliminates one,
conversion losses..]
Where do I go for more data on this aspect?
--
A host is a host from coast to coast.................wb8foz@nrk.com
& no one will talk to a host that's...
calculating loses